Genetics question - Page 1

So, a breeding I saw on the database a while back was like this.......  The sire was a sable, the dam was solid black.  However the litter only had bi-colors and dark sables.  The sires pedigree has no blacks in it, only sables and dark sables.  The dam is black, her sire is black, and then there are a couple of blacks on the bottom half of her pedigree as well.....So, if these two dogs can't produce black together, (since the sire obviously can't produce blacks since he was bred to another black female before as well) would a puppy of theirs be able to produce blacks if bred to a black....what about bred to a sable?  Anyway, not looking to do this, just curious about the genetics in this.

If the dam is solid black, all the puppies will be carriers for black and will able to produce it if bred to a black or a black carrier of any other colour.

Margaret N-J

If the pups where either Bi color or Sable it tells us right away because it was bred to a black dog that the Sable Sire carries one gene for the Sable (Expressed dominant gene) and one gene for Bi color. This sire can never produce black puppies as he lacks the black recessive gene. The Dam in this senario is pure black meaning she for sure is homozygous meaning both her genes are the black gene as the only way to express the black coat color is by having both genes be black.

What this means is that the puppies will either be Sable and carry the black gene or be Bi-Color and carry the black gene, in any situation all these pups will be able to produce black puppies (50% chance if with a black dog or 25% with a dog that carries the black gene) so long as the other dog carries the black gene.

Thanks guys.