by tbstone on 20 June 2018 - 15:06
I was just wondering if anyone could give me a clue what a color mating outcome would be if a puppy from http://www.pedigreedatabase.com/german_shepherd_dog/dog.html?id=2545924-jaegar-von-der-schwengel-haus and http://www.pedigreedatabase.com/german_shepherd_dog/dog.html?id=2181792-evie-von-bendlerblock was bred to http://www.pedigreedatabase.com/german_shepherd_dog/dog.html?id=2743443-brewster-vom-katgunn
The first 2 (Jaegar and Evie) sire and dam of potential puppy, are both sables, and the potential breeder (Brewster) of said puppy is black.
I am curious as to what color puppies could result being as there are bi-colors, blacks, and b/t in their ancestries.
by Swarnendu on 20 June 2018 - 17:06
A black mated to sable can give anything, Sable, Tan point or Black.
However, as the black parent is supplying a copy of black to all the offspring, chances are more there that you'll get darker sables and/or bi-color variety of tan point and/or black.
The research is still work in progress though....
by tbstone on 20 June 2018 - 19:06
Would that also hold true if the puppy is homozygous sable?
by Swarnendu on 20 June 2018 - 19:06
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