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by tina5 on 28 December 2006 - 12:12
question, would there be a chance of any sables in this color of breeding?
none known of in females pedigree. Tina
by laughter on 28 December 2006 - 12:12
Tina it would be very unlikely if no sables on the mothers side. But to check the fathers side would be a benefit. They would show a chance if any. But i feel it would be unlikely.
by neuen-polizei on 28 December 2006 - 12:12
No, there must be a sable parent in order to produce a sable pup. This combination will produce black/tan, bi-color, and if both parents carry the black recessive gene, solid black.
If either dog carried a sable gene, then they would have been sable themselves as that is the dominant color over all other colors.
Jeff
by gsdlvr2 on 28 December 2006 - 13:12
Flick von Arlett carried the sable gene from the mother line and he was black and red.
Arlett.de has alot of good info on sables
by tina5 on 28 December 2006 - 13:12
thanx a lot people!!
by gsdlvr2 on 28 December 2006 - 13:12
sorry, I just re-read my comment and realized I didn't answer your question. I think you will not get sable from that breeding if there are not any sables in parents,esp. mother line. My comment about Flick..he did produce sables and was black and red is what I meant but he had 4 generations of the sable gene in the mother line.
by Silbersee on 28 December 2006 - 14:12
gsdlvr2, Flick v. Arlett did not produce any sable offspring himself. As mentioned above, only if one of the parents is sable as well. But two sables can produce a black and red dog!
by Lynx on 28 December 2006 - 15:12
Flick couldn't produce any sable progeny without a sable bitch! No matter how many sable dogs he had in his pedigree, he has no sable gene himself!
by eichenluft on 28 December 2006 - 16:12
there is no - zero - zilch - never - any possibility of ANY sable puppies in ANY litter without at least one sable parent. Won't happen. Ever. Sable gene is dominant over all other colors, so if any dog carries a sable gene, that dog will BE a sable dog. Flick may have produced sable puppies, but only if bred to a sable female.
The combination of black/tan bred to black will produce black/tans. No bicolor unless the black/tan dog carries a bicolor "melanistic" gene "tag". No blacks unless the black/tan carries a black recessive. The black parent will produce darker puppies - but because they have more black coverage, the black will not improve red/tan pigment.
molly
molly
by gsdlvr2 on 28 December 2006 - 16:12
Ok guys..about Flick, I was only repeating what I read by the owner. If she was wrong..my mistake.
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