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by eichenluft on 05 July 2010 - 22:07
Not in the GSD breed - two non-sable parents can NOT produce a sable puppy - sable is ALWAYS dominant, so a dog that carries a sable gene IS a sable dog. No exceptions, except when you start talking about the masking genes (white, and..... black?) - but neither would include two black/tan parents producing a sable pup. NO CHANCE. There are no double recessive sable genes in GSDs. Sable is always dominant - only a sable dog can carry another sable "recessive" gene making it a homozygous sable.
molly
molly
by gsdlvr2 on 05 July 2010 - 22:07
Your information is either incomplete or outdated.
by eichenluft on 06 July 2010 - 01:07
ok, show me a sable dog from a litter born from a non-sable sire and dam, pedigree verified or DNA tested of course - and I'll show you a beach property in Kansas.
molly
molly
by gagsd4 on 06 July 2010 - 10:07
In the German Shepherd Dog, black is recessive. Sable is dominant.
If someone tried to sell me a sable puppy from non sable parents, I would run the other way.
--Mary
If someone tried to sell me a sable puppy from non sable parents, I would run the other way.
--Mary
by gsdlvr2 on 06 July 2010 - 12:07
The GSD in not an exception to the rest of the animal kingdom.
A double recessive can produce and unexpected anything whether color or something else. Exceptions to dominant genes do happen. Not common at all but it does happen. As long as the dominant gene carries the recessive gene and the same happens in the other parent a sable CAN (not WILL) be produced.
A double recessive can produce and unexpected anything whether color or something else. Exceptions to dominant genes do happen. Not common at all but it does happen. As long as the dominant gene carries the recessive gene and the same happens in the other parent a sable CAN (not WILL) be produced.
by eichenluft on 06 July 2010 - 12:07
EXAMPLES IN THE GERMAN SHEPHERD DOG that has been verified/DNA tested, please? The answer is - there isn't any. Theory is fine, but proof is in real facts. Real facts is that in the GSD breed, black is always recessive, sable is always dominant. You can argue until the end of time but without actual examples and proof, it's only theory. Interesting theory, but not factual in this breed.
molly
molly
by cage on 06 July 2010 - 14:07
by gsdlvr2 on 06 July 2010 - 22:07
molly- I understand what you are saying regarding sables and color genetics. What I have said is not theory, it is fact. No offense intended but your knowledge of genetics is rudimentary at best and frankly sounds like it came from a book written to explain the complex subject of genetics to lay people.
by eichenluft on 06 July 2010 - 22:07
How can it be fact without facts to back up the theory? There are no facts to back it up. NO real black dogs who have produced sable puppies when bred to a non-sable. NONE. NO sable puppies proven to be the product of two non-sable dogs. NONE. If you can't come up with proof of your THEORY, then how can you call it a fact?
molly
molly
by gsdlvr2 on 06 July 2010 - 22:07
Are you educated in genetics at all? Where does your understanding come from?
Perhaps I can make it simpler if I understand your knowledge base. If you want to understand, I will try to make it easy for you. If your goal is to challenge me and insist you are right then you are wasting my time.
Perhaps I can make it simpler if I understand your knowledge base. If you want to understand, I will try to make it easy for you. If your goal is to challenge me and insist you are right then you are wasting my time.
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