Conformation Showing > Mr. Donald asked me a difficult question (115 replies)
by Ibrahim on 16 June 2012 - 18:31 |
And let us look closely at the shoulder![]() |
by Ibrahim on 16 June 2012 - 18:32 |
And corresponding reach![]() |
by Ibrahim on 16 June 2012 - 18:33 |
| Now we see that the shoulder blade length has become more than the front upper arm. The sum of bone lengths is 33.6 cms with a decrease of 2.4 cms or 6.7% from that in the ideal shoulder. The sum of shoulder angles is 108 degrees. The front reach decreased 1.88 cms or 4.35%. One important note as the shoulder blade angle increases its length also increases (front upper arm angle remaining the same at 53 degrees) and ratio to front upper arm length decreases and so on till the shoulder blade length becomes more than the length of the front upper arm. As the shoulder blade angle increases (the front upper arm angle remaininng adeal at 53 degrees) the front reach decreases. Or in other words the smaller the shoulder blade angle the better the front reach is. |
by Ibrahim on 16 June 2012 - 19:26 |
| Please do not worry much about the conclusions, when at the end I make tabulations, the conclusions will be easier and more clear. |
by Ibrahim on 18 June 2012 - 16:55 |
| Page 9, 3nd diagram the fore arm'leg dimension should be corrected to read 19.2687 cms, I will correct the drawing. |
by Ibrahim on 19 June 2012 - 08:18 |
| I am making drawings of many shoulder bones combinations and I need to ask a question: Do you see GSDs whether show or work with shoulder blades longer than front upper arm? Anyone can answer to that. Ibrahim |
by Ibrahim on 19 June 2012 - 21:06 |
| Mr. Donald, I managed to verify the angles in Mr. Fred Lantings photo with the Autocad ![]() |
by Ibrahim on 19 June 2012 - 21:30 |
And here's Dingo![]() |
by Ibrahim on 19 June 2012 - 22:04 |
Dingo's case is similar to this one![]() |
by Ibrahim on 28 June 2012 - 20:03 |
Correcting that drawing, here is the correct one![]() |
by Ibrahim on 28 June 2012 - 20:23 |
In regards to the shoulder combination, what is important in the end for the fore front reach is the distance AB shown below.![]() |
by Ibrahim on 28 June 2012 - 20:44 |
| Also the fore front reach (AE) is actually the summation of 3 horizontal distances as shown below AB + CD + DE ![]() |
by Ibrahim on 28 June 2012 - 21:04 |
Please note that if front upper arm opens more than 90 degrees then we will have a fourth horizontal distance which is BC and thus fore front reach increases, in this case it is the number in pink.![]() |
by Ibrahim on 28 June 2012 - 21:27 |
I think that is the case with Dingo, I say I think because the point of shoulder might not be exactly where I drew it and in that case the angle might be less than 103 degrees, but my best guess it is more than 90 degrees, maybe 95 degrees !!!![]() |
by Ibrahim on 28 June 2012 - 21:54 |
But on the other hand if the dog can not open his front upper arm upto or little more than 90 degrees, and opens it short of the 90 degrees then that BC distance becomes negative (backwards) and will be deducted from the summation of the other three distances and fore front reach will become less as shown below![]() |
by Ruger1 on 30 June 2012 - 06:17 |
| Very interesting Ibrahim!..You are very dedicated to learning and research..I like that! |

















.jpg)
.jpg)